JEE Main Paper 2 Final Answer Key 2023 released on jeemain.nta.nic.in, download now – Times of India

JEE Main Paper 2 Final Answer Key 2023 released on jeemain.nta.nic.in, download now – Times of India

NEW DELHI: The National Testing Agency (NTA) has released the JEE Main Paper 2 Final Answer Key 2023. Candidates who appeared for the examination can check and download the final answer key from the official website – jeemain.nta.nic.in.
The Joint Entrance Examination (Main) – 2023 Session 1 was held at different exam centres located in 290 cities across the country and 18 cities outside India. The JEE Main Session 1 Paper 2 was conducted on January 28, 2023, in a second shift for B.Arch and B.Planning programmes.
Candidates can follow the step-by-step guide given below to download the JEE Main Final Answer Key 2023 for Paper 2. A direct link for the same has also been shared below the steps.
How to download JEE Main Paper 2 Final Answer Key 2023?
Step 1: Visit the official website at jeemain.nta.nic.in
Step 2: On the homepage, click on the link given for JEE Main Answer Key Paper 2.
Step 3: A new PDF file will be opened.
Step 4: Check the answers given in the final key and match them against your responses.
Step 5: Download the JEE Main Paper 2 Final Answer Key and take a printout of the same for further use.
Direct Link: Download Paper 2 Final Answer Key

However, the NTA is yet to declare the JEE Main Paper 2 result for the Session 1 exams. The date has not been confirmed as of now but as per the official final answer key, it is mentioned that the results of JEE Main Session 1 Paper 2 have been compiled on February 27, 2023.

!(function(f, b, e, v, n, t, s) {
window.TimesApps = window.TimesApps || {};
const { TimesApps } = window;
TimesApps.loadFBEvents = function() {
(function(f, b, e, v, n, t, s) {
if (f.fbq) return;
n = f.fbq = function() {
n.callMethod ? n.callMethod(…arguments) : n.queue.push(arguments);
};
if (!f._fbq) f._fbq = n;
n.push = n;
n.loaded = !0;
n.version = ‘2.0’;
n.queue = [];
t = b.createElement(e);
t.async = !0;
t.defer = !0;
t.src = v;
s = b.getElementsByTagName(e)[0];
s.parentNode.insertBefore(t, s);
})(f, b, e, v, n, t, s);
fbq(‘init’, ‘593671331875494’);
fbq(‘track’, ‘PageView’);
};
})(
window,
document,
‘script’,
‘https://connect.facebook.net/en_US/fbevents.js’,
);if(typeof window !== ‘undefined’) {
window.TimesApps = window.TimesApps || {};
const { TimesApps } = window;
TimesApps.loadScriptsOnceAdsReady = () => {
var scripts = [
‘https://www.googletagmanager.com/gtag/js?id=AW-877820074’,
‘https://www.googletagmanager.com/gtag/js?id=AW-658129294’,
‘https://timesofindia.indiatimes.com/grxpushnotification_js/minify-1,version-2.cms’,
‘https://connect.facebook.net/en_US/sdk.js#version=v10.0&xfbml=true’,
‘https://timesofindia.indiatimes.com/locateservice_js/minify-1,version-14.cms’
];
scripts.forEach(function(url) {
let script = document.createElement(‘script’);
script.type=”text/javascript”;
if(!false && !false && !false && url.indexOf(‘colombia_v2’)!== -1){
script.src = url;
} else if (!false && !false && !false && url.indexOf(‘sdkloader’)!== -1) {
script.src = url;
} else if (!false && (url.indexOf(‘tvid.in/sdk’) !== -1 || url.indexOf(‘connect.facebook.net’) !== -1 || url.indexOf(‘locateservice_js’) !== -1 )) {
script.src = url;
} else if (url.indexOf(‘colombia_v2’)== -1 && url.indexOf(‘sdkloader’)== -1 && url.indexOf(‘tvid.in/sdk’)== -1 && url.indexOf(‘connect.facebook.net’) == -1){
script.src = url;
}
script.async = true;
script.defer = true;
document.body.appendChild(script);
});
}
}

Source link